2m^2+19=-35

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Solution for 2m^2+19=-35 equation: 



2m^2+19=-35

We move all terms to the left:

2m^2+19-(-35)=0

We add all the numbers together, and all the variables

2m^2+54=0

a = 2; b = 0; c = +54;
Δ = b2-4ac
Δ = 02-4·2·54
Δ = -432
Delta is less than zero, so there is no solution for the equation

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